Question

A rectangular tank 15 m long and 11m board is needed to transfer the entire liquid from a full cylindrical tank of internal diameter 21m and length 5m. Find the least height of the tank that will serve the purpose.

Answer 1

Answer:

hey dude here is your answer

Let the height of rectangular tank be h

Length of rectangular tank = 15 m

width of rectangular tank = 11 m

Volume of tank = Length \times width \times heightLength×width×height

= 15\times 11 \times h15×11×h

= 165 h165h

Diameter of cylinder = 21 m

radius of cylinder = Diameter /2 = 21 /2 = 10.5 m

Height of Cylindrical tank = 5 m

Volume of cylindrical tank = \pi r^2 hπr

2

h

= 3.14 \times (10.5)^2 \times 53.14×(10.5)

2

×5

= 1730.9251730.925

Since we are given that a rectangular tank is needed to transfer the entire liquid from a full cylindrical tank .

So, Volume will remain same .

So, 165 h= 1730.925165h=1730.925

h= \frac{1730.925}{165}h=

165

1730.925

h=10.490h=10.490

Thus the height of the tank that will serve the purpose is 10.49 m

I hope my answer help you

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Answer 2

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Let the height of rectangular tank be h

Length of rectangular tank= 15m

Width of rectangular tank= 11m

Volume of tank= Length×Breadth×height

=15×11×h

= 165h

Diameter of cylinder = 21m

Radius of cylinder= Diameter /2

= 21/2

=10.5m

Height of cylindrical tank= $\pi {r}^{2}h$

= $3.14 \times {10.5}^{2} \times 5$

= $1730.925$

Since, we are given that a rectangular tank is needed to transfer the entire liquid from a full cylindrical tank.

So, volume will remain same.

So,

$165h = 1730.925$

$h = \frac{1730.925}{165}$

$h = 10.490m$