Question

A rectangular tank is 10m long 5m broad and 3m high. It is filled up to the rim with water. Calculate the thrust at the bottom and the walls of the tank due to hydrostatic pressure

Answer 1

Hello dear,

● Answer-
Pb = 3×10^4 Pa
Ps1 = 5×10^4 Pa
Ps2 = 10^5 Pa

● Explaination-
# Given-
l = 10 m
b = 5 m
h = 3 m
d = 1000 kg/m^3

# Solution-
Weight of water is -
W = Mg = Vdg
W = lbhdg
W = 10×5×3×1000×10
W = 1.5×10^6 N

Thrust on bottom is-
Pb = F / A = W / lb
Pb = 1.5×10^6 / 10×5
Pb = 3×10^4 Pa

Thrust on side 1
Ps1 = F / A = W / lh
Ps1 = 1.5×10^6 / 10×3
Ps1 = 5×10^4 Pa

Thrust on side 2
Ps2 = F / A = W / bh
Ps2 = 1.5×10^6 / 5×3
Ps2 = 10^5 Pa

Hope this is helpful...