Question

A rectangular tank measuring 5m x 4.5m x 2.1m is dug in the
centre of field measuring 13.5m x 7.5m. The earth dug out is
spread evenly over the remaining portion of the field. By how
much is the level of the field raised?
(3)




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Answer 1

Answer:

. If x = - 4 then find the value of 5 x2

– 3x + 7.

Answer 2

Answer:

4.2 m is the answer.

Step-by-step explanation:

We have ,

Area of the field = (13.5 × 2.5) m² = 33.75 m²

Volume of the earth dug out = Vol. of the tank

= (5 × 4.5 × 2.1) m³ = 47.25 m³

Area of the tank = (5 × 4.5) m² = 22.5 m²

_____________________

Area on which the earth dug out has been spread

= area of the field - area of the tank = (33.75 - 22.5) m² = 11.25 m²

∴ Level raised

$= \frac{area \:of \:earth \:dug \:out}{area\: of\: which\: the \:earth\: is\: spread}$

$= \frac{47.25}{11.25} = 4.2 m$