A rectangular tank of base 100 m2has a height of 2m. Calculate the thrust at the bottom of the tank, if it is filled upto the brim with water of density 103 kg m-3 ?
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Answer:
Given that,
density of water (ρ)=10^3 Kg/m^3
water fixed up till height (h)=2 m
Area of base (A)=100 m^2 .
assuming atmospheric pressure (Pa) = 1 atm≃10^5 Pa
so, pressure at bottom of tank,
P=Pa +ρgh
=10^5 + 10^3 x 10 x 2
P=(1.2×10^5)Pa
Thus, thrust on bottom surface,
F=P.A=(1.2×10^5)×10^2⇒F=1.2×10^7 N
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