Question

A rectangular tank of base area 100m and of height 2m calculate thrust at bottom of tank if water is filled up to brim of density 1000kg/m

Answer 1

base area of tank = 100 m^2

height = 2m

volume = base area × height = 100×2 = 200 m^2

density of water = 1000kg/m^3

mass of water = density× volume = 1000×200 = 2×10^5 kg

thrust Force = mg = 2×10^5 × 10 = 2×10^6 N

Thrust force is 2×10^6 N

Answer 2

Concept

Recall some formulas that will use

1. volume = base area × height

2. mass of water = density× volume

3.  Force = mg

Where m is mass and g is acceleration.

Given

A rectangular tank of base area 100m and of height 2m.

To find

The thrust at bottom of tank.

Solutions

First we have to find the volume of brim

V = 100×2

  = 200 m²

now the mass of water = density× volume

                                      = 1000×200

                                      = 2×$10^5$ kg

We know density of water = 1000 $kg/m^3$

thrust Force = 2×$10^5$ × 10

                    = 2×$10^6$ N

Hence thrust force is 2×$10^6$N