A rectangular tank of base area 100m and of height 2m calculate thrust at bottom of tank if water is filled up to brim of density 1000kg/m
Answers
Answered by
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base area of tank = 100 m^2
height = 2m
volume = base area × height = 100×2 = 200 m^2
density of water = 1000kg/m^3
mass of water = density× volume = 1000×200 = 2×10^5 kg
thrust Force = mg = 2×10^5 × 10 = 2×10^6 N
Thrust force is 2×10^6 N
height = 2m
volume = base area × height = 100×2 = 200 m^2
density of water = 1000kg/m^3
mass of water = density× volume = 1000×200 = 2×10^5 kg
thrust Force = mg = 2×10^5 × 10 = 2×10^6 N
Thrust force is 2×10^6 N
vishesh84:
i think its answer is 700
Answered by
1
Concept
Recall some formulas that will use
1. volume = base area × height
2. mass of water = density× volume
3. Force = mg
Where m is mass and g is acceleration.
Given
A rectangular tank of base area 100m and of height 2m.
To find
The thrust at bottom of tank.
Solutions
First we have to find the volume of brim
V = 100×2
= 200 m²
now the mass of water = density× volume
= 1000×200
= 2× kg
We know density of water = 1000
thrust Force = 2× × 10
= 2× N
Hence thrust force is 2×N
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