Question

a rectangular track is 40m long and 30m broad. a man starts walking from one corner of the track and reaches the opposite corner . find the distance traveled and the magnitude of the displacement.

Answer 1

$\mathfrak{\large{\underline{\underline{Given:-}}}}$

Length of rectangular track = 40 m

Breadth of rectangular track = 30 m

$\mathfrak{\large{\underline{\underline{To find :-}}}}$

Distance travelled by man = ?

Displacement by man = ?

$\mathfrak{\large{\underline{\underline{Solution:-}}}}$

Since, man is started from one corner and reaches the opposite corner .

Let ABCD be the rectangle given in attachment.

AB = DC = 40 m

AD = BC = 30 m

Let the man start from corner d and move to corner B.

Then distance travelled by man = AD + AB

= 30 + 40

= 70 m.

Displacement of man is given by diagonal of rectangle.

Displacement of man = $\bold{DB = \sqrt{ {(DA) }^{2} + {(AB) }^{2} } }$

$\implies$ $\bold{DB= \sqrt{ {30}^{2} + {40}^{2} } }$

$\implies$ $\bold{DB = \sqrt{2500} }$

$\implies$ $\bold{DB = 50 m}$

hence, displacement of man is 50m.

Answer 2

Answer:

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Explanation:

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