a rectangular water reservoir contains 42000 litres of water .find the depth of the water if its base measures 6m by 3.5m
Answers
Answered by
196
Given length of the rectangular reservoir [cuboid] = l = 6m
Breadth = b = 3.5m
Let the Depth(height) of the cuboid be `h`
Given volume = 42000 litre = 42m³
We know that the volume of a cuboid = lbh
⇒6m × 3.5m × `h`m = 42m³
⇒21h m³ = 42m³
⇒h = 42m³/21m³
∴h = 2m
∴The depth of the reservoir is 2m
Breadth = b = 3.5m
Let the Depth(height) of the cuboid be `h`
Given volume = 42000 litre = 42m³
We know that the volume of a cuboid = lbh
⇒6m × 3.5m × `h`m = 42m³
⇒21h m³ = 42m³
⇒h = 42m³/21m³
∴h = 2m
∴The depth of the reservoir is 2m
Answered by
111
as we know that, 1000 L = 1 m³
so, 42000 L = 42 m³
now, Let the depth of water in reservoir = h m
then volume of water in reservoir = (6×3.5×h) m³
A/q,
(6×3.5×h) =42
⇒ h= 42/21
=2 m
∴depth of reservoir is 2 m
so, 42000 L = 42 m³
now, Let the depth of water in reservoir = h m
then volume of water in reservoir = (6×3.5×h) m³
A/q,
(6×3.5×h) =42
⇒ h= 42/21
=2 m
∴depth of reservoir is 2 m
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