a reduction of 20% in price of sugar unable to reach 6kg more sugar for 960₹ . what is the reduced rate of per kg
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₹10 per kg
STEP BY EXPLANATION:
Before reduction of cost.
let X kg purchase by at rupees 120
the price of 1kg=(120/x) ------------(1)
now after reduction of cost (x+3)kg can we purchase.
price of 1kg =(₹120 /x+3)----------―――――-------(2)
the price at 20% decreas
=120/x-(20/100×120/x)
=120/x-24/x120/x+ 3
=96/x=120/x+3
=24x=288
x=12
previously 12 kg of sugar can we purchase at ₹120
original price =120/x. ―――[using]
=120/12=₹10.
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