Question

A reduction of 25% in the price of apple would enable a purchaser to get 2 kg weight Apples more for ₹ 240

Find -

• the reduced price per kg weight of apples

• the original price per kg weight of Apples

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Answer 1

Answer:

A reduction of 25% in the price of apples would enable a purchaser to get 2 kg apples more for Rs. 240. Find the original price per kg of apples.

₹ 35

₹ 30

₹ 40

None of these

Correct Option: C

Let the original price be ₹ x per kg

Reduction in price = ₹

25

x

100

∴ Reduced price = x –

25

x

100

=

75

x ..............................(i)

100

With ₹ 240, purchaser can purchase 2 kg more apples.

Now, 25% of 240

=

25

× 240 = ₹ 60

100

⇒ Reduced price of 2 kg of apples = Rs. 60

∴ Reduced price of 1 kg of apples = 30 ............. (ii)

From equations (i) and (ii),

=

75

× x = 30

100

⇒ x =

30 × 100

= ₹ 40

75

The original price of 1 kg apples = Rs. 40

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Answer 2

QUESTION -

A reduction of 25% in the price of apple would enable a purchaser to get 2 kg weight Apples more for ₹ 240

Find -

• the reduced price per kg weight of apples

• the original price per kg weight of Apples

ANSWER -

the reduced price per kg weight of apples

→ rs 30

the original price per kg weight of Apples

→ rs 40

SOLUTION -

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{cccc}\sf &\sf Rate&\sf Weight&\sf Cost(₹)\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}\\\sf Initial &\sf x &\sf y &\sf 240 \\\\\sf Final &\sf \dfrac{x - 25}{100}x &\sf y + 2 &\sf 240 \\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{\bf{}}&\frac{ \qquad \qquad \qquad \qquad\qquad}{}&\frac{ \qquad \qquad \qquad \qquad\qquad}{}\end{array}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$

★ xy = 240

$\begin{gathered} \sf \longrightarrow xy = \dfrac{3}{4}x \: (y + 2) \\ \end{gathered}$

$\begin{gathered} \sf \longrightarrow 240 = \dfrac{3}{4}xy + \frac{6}{4} x \\ \end{gathered}$

$\begin{gathered} \sf \longrightarrow 240 = \dfrac{3}{ \cancel{4}} \times \cancel{240} + \frac{6}{4} x \\ \end{gathered}$

$\begin{gathered} \sf \longrightarrow 60 = \frac{6}{4} x \\ \end{gathered}$

$\begin{gathered} \sf \longrightarrow x = \frac{60 \times 4}{6} \\ \end{gathered}$

$\begin{gathered} \sf \longrightarrow x = \frac{ \cancel{60} \times 4}{ \cancel{6}} = 40\\ \end{gathered}$

∴ Reduced Price = $\begin{gathered} \sf 40 - \frac{25}{100} \\ \end{gathered} = \sf \: rs \: 30$

∴ Original price = rs 40