Question

A refigerator does 153 J of work to transfer 568 J of heat from its cold compartment. (a) Calculate the refrigerator’s coefficient of performance, (b) How much heat is exhausted to the kitchen?

Answer 1

Answer:

Solution:-

(a) To obtain the coefficient of performance K of refrigerator, substitute 568 J for extracted heat QL and 153 J for the work W in the equation K = QL/W,

K = QL/W

= 568 J/153 J

= 3.71

Therefore, the coefficient of performance K of refrigerator would be 3.71.

(b)  To obtain exhausted heat to the kitchen by refrigerator, substitute 153 J for the work W  and 568 J for extracted heat QL in the equation QH = W + QL,

QH = W + QL

= 153 J + 568 J

= 721 J

Therefore, exhausted heat to the kitchen by refrigerator would be 721 J

Answer 2

Answer:

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Explanation:

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