Question

a refrigerator has purchased one year ago for rupees 20000. it value depreciates at the rate of 15% per annum. find :
(i) it's present value
(ii) it's value after 1 year.
​please tell me the answer

Answer 1

Answer:

The present value of the refrigerator after 1 year is 23529.41 whereas its value after 1 year is 17000.

Step-by-step explanation:

Step 1: We first write down the necessary formulas in this question.

Formula for present value = PV

Where P = Principal value.

V = the present value factor and in this case its equal to :

V = 1/(1 - i)ⁿ

n = Time in years

I = rate of depreciation.

Value after n years = P(1 - i)ⁿ

Step 2: Identify the given values.

i = 15%

P = Rupees 20000

Step 3 : Answer the questions.

I) The present value after 1 year

= 20000 × 1/(1 - 0.15)¹

= 23529.41

Ii) Value after 1 year.

= 20000(1 - 0.15)¹ = 17000

Answer 2

Answer:

a)Cost price of Refrigerator 20,000

Cost price of Refrigerator 20,000Rate of decrease is 15%

Decreased amount is

15/100 ×20,000=3,000

So the present price is 20,000−3,000=17,000

b)Decrease amount a year after is

Decrease amount a year after is 15/100 ×17,000=2550

Decrease amount a year after is 15/100 ×17,000=2550So the price is 17,000−2,550=14,450Rs.