Question

A refrigerator has to transfer an average of 263 J of heat per second from temperature -10°C to 25°C find power consumers of no energy is lost !!
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Answer 1

Hey!
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Ques. → A refrigerator has to transfer an average of 263 J of heat per second from temperature -10°C to 25°C find power consumed if no energy is lost .

Solution →

◾Q2 = 263 Js^-1

◾T2 = -10°C = 263 K

◾T1 = 25°C = 298 K

{ Add 273 to the Celsius temperature to change it to Kelvin ]

=> Power = Work / Time

$= > \beta = \frac{q2}{w} = \frac{t2}{t2 - t1}$

$= > work \: done \: w \: = \frac{q2(t1 - t2)}{t2} \\ \\ = > w = \frac{263(298 - 263)}{263}$

•°• Work done : 35 Js^-1

✔Now , Power is equal to work done in unit time. So here we have ,

Work = 35 J and Time = 1 second.

⭐❗Power = 35 Watts ✔

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Answer 2

Power = Work / Time

So answer is 35 w