A refrigerator works between 4°C and 30°C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is: (Take 1 cal = 4.2 joules)(a) 2.365 W(b) 23.65 W(c) 236.5 W(d) 2365 W
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Answered by
7
C.O.P. = Heat extracted / effort put
= T2 / T1 -T2 ; T2 < T1
for 1 second analysis
(600)(4.2) / Effort put = 277/26
Effort put = 236.5 J / Power = 236.5 watt
= T2 / T1 -T2 ; T2 < T1
for 1 second analysis
(600)(4.2) / Effort put = 277/26
Effort put = 236.5 J / Power = 236.5 watt
Answered by
2
Heya...!!!
Answer is...
236.5
Thank you..☺️
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