Question

A regular hexagon of side 10 cm has a change 5 micro coulomb at each of its vertices. calculate the potential at the centre of the hexagon.

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Answer 1

regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. ... Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.

hope it helps you

Answer 2

To Find:-

• Calculate the potential at the centre of the hexagon.

Solution:-

Here ,

$\tt\implies \: V = K \times \dfrac { Q } { r }$

$\tt\implies \: V = \dfrac { 9 \times { 10 }^{ 9 } \times 5 \times { 10 }^{ -6 } } { 0.1 }$

$\tt\implies \: V = \dfrac { 45 \times { 10 }^{ 3 } } { 0.1 }$

$\tt\implies \: V = 450 \times { 10 }^{ 3 }$

Now ,

Potential Energy:-

$\tt\implies \: V = 6V$

$\tt\implies \: V = 6 \times 450 \times { 10 }^{ 3 }$

$\tt\implies \: V = 2.7 \times { 10 }^{ 6 }$

Hence ,

$\tt \: 2.7 \times { 10 }^{ 6 }$