Question

A remote sensing satellite is moving around the earth in an orbit whose altitude from the surface of earth is 800km​

Answer 1

#BAL

Orbital velocity = 7.455 × 10^6 m/s

Time Period T = 1.69 hour

Explanation:

Given

Height of the satellite h = 800 km

R = Re + h = 6400 + 800 = 7200 km = 7.2 × 10^6 m

Orbital velocity of the satellite is given by

Taking the following data

Radius of earth Re = 6400 km

Mass of the earth Me = 6 × 10^24 kg

G = 6.67 × 10^-11 N-m²/kg²

V= √ GMe/R

= V= √ 6.67*10−¹¹ * 6* 10−²⁴

= 7.2*10⁶

= V = 7.455*10³ m/s

Calculation of time period using

T² = 4π² (7.2*10⁶)³

 = 6.67*10−¹¹ *6*10−²⁴

T = 2π * √9.3265*10⁵

T = 2π * 9.657*10²

T = 6067.67sec OR T = 1.69hour