Question

A resistance of 10 Ω is connected in series with two resistances each of

15 Ω arranged in parallel. An unknown resistance is connected across this

parallel combination. Determine the power consumed by the unknown

resistance. The total current and voltage is 1.5 A, 20 V.​

Answer 1

Answer:

The circuit connections are shown in Fig. 1.46. Drop across 10-Ω resistor = 1.5 × 10 = 15 V Drop across parallel combination VAB = 20 − 15 = 5 V Hence voltage across each parallel resistance is 5V. I1 = 5/15 = 1/3 A I2 = 5/15 = 1/3A I3 = 1.5 − 1/3 + 1/3 = 5/6 A ∴ I3R = 5 or 5/6 R = 5 or R = 6Ω