Physics, asked by ponamirtha66713, 8 months ago

A resistance of 3Ω is connected in series with 5Ω. This connection is kept in parallel with a 8Ω resistance. The current in 5Ω resistance if 24V potential difference is applied is?​

Answers

Answered by juhi2503
0

Explanation:

Equivalent resistance of the parallel resistors=3×63+6=2ΩEquivalent resistance of the parallel resistors=3×63+6=2Ω

Total resistance of the circuit=2+3=5ΩTotal resistance of the circuit=2+3=5Ω

Current flowing in the circuit=55=1ACurrent flowing in the circuit=55=1A

current passing through6Ωresistorcurrent passing through6Ωresistor

=33+6(1)=13A=33+6(1)=13A

Voltage drop across6Ω resistor=13(6)=2V

this is your answer may be its help you

Answered by uddhavsingh2k183630
0

Answer:

Equivalent resistance of the parallel resistors=3×63+6=2ΩEquivalent resistance of the parallel resistors=3×63+6=2Ω

Total resistance of the circuit=2+3=5ΩTotal resistance of the circuit=2+3=5Ω

Current flowing in the circuit=55=1ACurrent flowing in the circuit=55=1A

current passing through6Ωresistorcurrent passing through6Ωresistor

=33+6(1)=13A=33+6(1)=13A

Voltage drop across6Ω resistor=13(6)=2V

Explanation:

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