Question

A resistance of 40 ohms and one of 60 ohms are arranged in series across 220 volt supply. Find the heat in joules produced by this combination of resistances in half a minute.

Answer 1

$h = {i}^{2} \: \times r \times t$

r= 40+60

=100 ohms

v=i*r

I= v/r

= 220/100

= 22/10 ohms

t=30s

H=22/10^2 x 100x30

= 484x30

= 14520 J

Answer 2

Answer:

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