A resistance of 6 ohm is connected in series with another resistance of 4 ohm. A potential difference of 20 volt is applied across the combination. Calculate the current through the circuit and potential difference across the 6 ohm resistance.
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Answer:
i = 2A V (6 ohm resistor) = 12 V
Explanation:
Since the resistors are connected in series,
R(total) = 6 + 4 = 10 ohms
We know that V = IR
=> I = V/R
.°. I = 20÷10 = 2A
And, since V = IR,
Pd across the 6 ohm resistor will be,
V = 2 A × 6 ohms = 12 V
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