A resistance of a capital sister of capacitance C is x if both the frequency and the capacitance be doubled the new reactance will be
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Hello
Explanation:
Express 0.134 bar in p/q form (only 3 and 4 have bar)
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If the capacitor of capacitance C is connected with an AC single, then reactance of that circuit is purely capacutive
The capacitive reactance is
X = 1 /ωC = 1/2 πfC _[ω = 2πf ]
X ∝ 1/fC
Considering two different situations of frequency and capacitance, we have
=> X'/ X = fC / f' C' = ( f × C ) / ( 2f × 2C )
...[ f' = 2f and C' = 2C ]
=> X' / X = 1/4
=> X' = X / 4
The new reactance will be X/4 !
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