Physics, asked by pachaurishubham2000, 10 months ago

A Resistance of R of thermal coefficient of resistivity α(alpha) is connected in parallel with a resistance 3R having thermal coefficient of resistivity 2α(2alpha).Equivalent thermal coefficient or resistivity for the combination is
1. 7α/4 2. 5α/4
3. 9α/4 4.3α/2

Answers

Answered by vva40
7

Explanation:

equivalent thermal coefficient in parallel is( a2R1+a1R2)/(R1+R2)

=(2aR+3aR)/(R+3R)

=5a/4

ans is option 2

Answered by NITESH761
0

Answer:

option (2)

Explanation:

The equivalent resistance at 0°C is

\sf \dfrac{R_{10}  R_{20}}{R_{10}+R_{20}}

The equivalent resistance at t°C is

\sf \dfrac{R_{1}R_{2}}{R_{1}+R_{2}}

\sf R_1 = R_{10} (1+α t)

\sf R_2 = R_{20} (1+2α t)

\sf R = R_{0} (1+α_{eff} t)

\sf \alpha_{eff}=\dfrac{5}{4} α

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