Physics, asked by akihsir739, 1 year ago

A resistor of 10 k Ω having tolerance 10% is connected in series with another resistor of 20 k Ω having tolerance 20%. The tolerance of the combination will be(a) 10%(b) 13%(c) 30%(d) 20%

Answers

Answered by mihirsingh994
16
mark as BRAINLIEST ANSWER
in place of 10 mark as 6
Propagation of error through mathematical operations:

When adding or subtracting quantities, their errors add.
When any number of quantities are multiplied or divided, their percentage error add.
So, if two resistors are connected in series, then the effective resistance is addition of individual resistance values. Hence according to rule one above, the values of their error will add.

10% of 6k is 600 ohm and 10% of 4k is 400 ohm hence the answer in this case is 1000 ohm, which is interestingly 10% of 10k.

If these resistors are connected in parallel, then the effective resistance is given by (R1*R2)/(R1+R2).

Note that the denominator here is again addition of both resistor values hence it will give an error of 1000 ohm or 10% of 10k.
According to rule 2 above, the numerator will have an error of 20% (10%+10%=20%).
When we divide numerator by denominator, again percentage errors will get added (20% for N+ 10% for D= 30%)
Hence parallel combination will give 30% error.
Edit 1: As pointed out by Phil chalk, the resistance tolerance indeed remains 10% for the parallel combination of resistance, as opposed to 30% calculated by me in the original answer.
The reason being the original expression of parallel resistance combination is 1/(1/R1+1/R2). The expression (R1*R2)/(R1+R2) have redundant terms hence the tolerance I got earlier was wrong.
Answered by Anonymous
10

Answer:

C) 30%

Explanation:

R1 = 10K & Tolerance is 10%

10K = 10000 Ohms

10% of 10K = 1000 Ohms

Therefore, R1 Min = 10000- 1000 = 9000 = 9K

R1 max = 10000 + 1000 = 11000 = 11.1K

R2 = 20K & Tolerance = 20%

20K = 20000 ohms

R2 Min = 20000–4000 = 16000 = 16K

R2 Max = 20000+4000 = 24000 = 24K

In series the total Resistance = R1+R2

R1 Min+ R2 Min = 9K+16K = 25K

R1 Max + R2 Max = 11+ 24K = 35K

Nominal Value of Series is R1+R2 = 20K +10K = 30K

Overall tolerance = +/- 30%

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