Question

A resistor of 10 ohm connected across a cell of emf 12 V. draws the current of 1.1 A.
Find the internal resistance of the cell.
(1) 10 ohm
(2)0.1 ohm
(3)10.9 ohm
(4)0.91 ohm​

Answer 1

Explanation:

Let IR be the internal resistance. In absence of the internal resistance

the current should have been 1.2 A. It has been reduced because of the

internal resistance in series.

TotalresistanceIR+10=121.1=10.909

⟹IR=0.909Ω