Question

a resistor of 50 ohm an inductor of 20/pi h and a capacitor of 5/pi microfarad are connected in series to an ac source 230v 50hz find the current in circuit

Answer 1

Dear Student,

◆ Answer -

I = 4.6 A

◆ Explaination -

In given LCR circuit -

Xl = 2πfL

Xl = 2π × 50 × 20/π

Xl = 2000 ohm

Also,

Xc = 1/(2πfC)

Xc = 1 / (2π × 50 × 5/π × 10^-6)

Xc = 2000 ohm

Impendence of circuit will be -

Z = √[R^2 + (Xl-Xc)^2]

Z = √[50^2 + (2000-2000)^2]

Z = √(50^2)

Z = 50 ohm

Current in the circuit will be -

I = V / Z

I = 230 / 50

I = 4.6 A

Therefore, current in the circuit is 4.6 A.

Hope this is helpful ...

Answer 2

Explanation:

hope it will be helpful.