Question

A resistor of 8 Ω is connected in parallel with another resistor of X Ω. The resultant resistance of the combination is 4.8 ohm. What is the value of resistor X

Answer 1

Answer:

The value of resistor X is 12 ohm.

Answer 2

Answer:

Resistor X = 12 Ω

Explanation:

We have been given

Resistors of R ₁ = 8 Ω connected in parallel

Resistor R ₂ =  X Ω

And now the resultant resistance is R = 4.8 Ω

Now,

We know that

Now

Parallel resistor the voltage is same across each resistors  according to Voltage law .

$Resultant\ resistance\ is= \dfrac{1}{R} = \dfrac{1}{R1 } + \dfrac{1}{R2}\\\dfrac{1}{4.8} = \dfrac{1}{8} +\dfrac{1}{X} \\\\\dfrac{1}{X} =\dfrac{1}{4.8} +\dfrac{1}{8} \\\\\dfrac{1}{X} =\dfrac{1}{8} \\\\[/tex}$

Resistor X = 12 Ω