Physics, asked by asba6989, 1 year ago

A resistor of 8ohm is connected in parllel with another resistor X. The resultant resistance of the combination is 4.8ohm.what is the lue of X ???

Answers

Answered by maanlakha
0

Answer: we know that for parallel combination of resitors :

1/R= 1 /r1 +1 /r2

1/R=r1+r2 / r1*r2

R= r1* r2 / r1 +r2

Given R=4.8

r1= 8

r2= X

4.8= 8X / 8+X

4.8(8+X)=8X

38.4 + 4.8X = 8X

38.4= 8X- 4.8X

38.4= 3.2X

X= 38.4 /3.2

X= 12

Explanation:

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