A resistor of 8ohm is connected in parllel with another resistor X. The resultant resistance of the combination is 4.8ohm.what is the lue of X ???
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Answer: we know that for parallel combination of resitors :
1/R= 1 /r1 +1 /r2
1/R=r1+r2 / r1*r2
R= r1* r2 / r1 +r2
Given R=4.8
r1= 8
r2= X
4.8= 8X / 8+X
4.8(8+X)=8X
38.4 + 4.8X = 8X
38.4= 8X- 4.8X
38.4= 3.2X
X= 38.4 /3.2
X= 12
Explanation:
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