Physics, asked by garvagarwal181, 1 year ago

A resistor r is connected to a parallel combination of two identical batteries each with emf e and an internal resistance rthe potential drop across the resistance r is

Answers

Answered by gadakhsanket
1

Dear Student,

◆ Answer -

Vr = 4e/3

● Explanation -

Equivalent resistance in the circuit is -

R = r + r×r/(r+r)

R = r + r/2

R = 3r/2

Total voltage across the circuit will be -

V = e + e

V = 2e

Current in the circuit is -

I = V/R

I = 2e/(3r/2)

I = 4e/3r

Potential drop across resistance r is -

Vr = Ir

Vr = 4e/3r × r

Vr = 4e/3

Therefore, potential drop across resistance r is 4e/3.

Hope this helps you...

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