Question

A resistors of 8 ohm is connected in parallel with another resistor X the resultant resistance of the combination is 4.8 ohm what is the volume of resistor X

Answer 1

As the two resistance are R1 and R2,

Therefore the resultant resistant will be = 1/ R

= 1/R1+1/R2

Where R = 4.8 ohm,

R1= 8ohms,

R2= X ohms,

1/4.8 =1/8+1/X

10/48 = 8+x/8x

10(8x) =(8+x)48

80x-48x=384

32x=384

x=12 ohms.  ANSWER