Question

A restaurant hall is 20 metre long, 15 metre wide and 5 metre high. Its interior has to be covered with mat.
What will be the total expenditure if it costs $ 60 per square metre?
a) $64000 b) $57000 c) $52000 d) $45000

Answer 1

Answer:

The cost of putting the mat is $ 57,000.

Step-by-step explanation:

Given :

Length = 20 m

Width = 15 m

Height = 5 m

Rate = $ 60 per sq.m

To Find :

The total expenditure

Solution :

Find the Total surface area of hall -

⇒ 2[lh + bh + lb]

⇒ 2[20 × 5 + 15 × 5 + 20 × 15]

⇒ 2[100 + 75 + 300]

⇒ 2[475]

⇒ 950 m²

$\rule{300}{1.5}$

Cost of putting the mat -

⇒ 950 × 6

⇒ 57000

Therefore, the cost of putting the mat is $ 57,000.

Answer 2

Answer:

⋆ DIAGRAM :

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\put(8,5.5){20 m}\put(4,6.3){15 m}\put(11.2,7.5){5 m}\end{picture}$

$\rule{100}{1}$

$\underline{\bigstar\:\:\textsf{Total Surface Area of Hall :}}$

$:\implies\tt TSA=2[lb+bh+hl]\\\\\\:\implies\tt TSA=2[(20 \times 15)+(15 \times 5)+(5 \times 20)]\\\\\\:\implies\tt TSA=2[300+75+100]\\\\\\:\implies\tt TSA=2 \times 475\:m^2\\\\\\:\implies\tt TSA=950\:m^2$

$\rule{180}{2}$

$\underline{\bigstar\:\:\textsf{Cost of matting of Hall :}}$

$\dashrightarrow\tt\:\:Cost=TSA \times Rate\\\\\\\dashrightarrow\tt\:\:Cost=950\:m^2 \times \ \:60\:m^{-2}\\\\\\\dashrightarrow\tt\:\:Cost=950 \times \ \:60\\\\\\\dashrightarrow\tt\:\:\underline{\boxed{\textsf{\textbf{Cost = \ 57,000}}}}$

⠀

$\therefore\:\underline{\textsf{Total Expenditure of hall is b) \textbf{\ 57,000}}}.$