Question

a rhombus and a square have the same area. the side of the square is 6 cm. if one diagonal of the rhombus is 4 cm, find the length of the other diagonal​

Answer 1

Area of Square =Area of Rhombus

Side of Square=6cm

Area of a Square=Side²

=6²

=36 cm²

Area of Square=36 cm²

As we know Rhombus and Square have Same Area

Area of Rhombus=36 cm²

One of The Diagonal of Rhombus=4 cm

Let other Diagonal=x cm

Area of Rhombus when Diagonals are given.

$area = \frac{1}{2} \times diagonal1 \times diagonal2 \\ \\ \frac{1}{2} \times 4 \times x = 36 \\ \\ x = 36 \times \frac{2}{4} \\ \\ x = 9 \times 2 \\ \\ x = 18$

Length of Other Diagonal=18 cm.

➡️Square is 4 sided Figure in which Each Sides are Equal.

➡️Have Total Angle of 360°

➡️Have Two Diagonals of same Length

➡️Rhombus is also 4 sided Figure

➡️Have Total Angle of 360°

➡️It have 2 diagonals Of Different length