Question

pls anyone solve this all problems
I'm giving 100 points so do all problems humble request
don't spam if u spam ur a stupid

Answer 1

Bro Question 8,9,10 same tarike se legega

Answer 2

Hey mate here is your answer

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Your 7,8,9,10 question is done vy this method as

●proove that root 3 is irrartional

suppose 3–√ is rational, then 3–√=ab for some (a,b) suppose we have a/b in simplest form.

3–√a2=ab=3b2

if b is even, then a is also even in which case a/b is not in simplest form.

if b is odd then a is also odd. Therefore:

ab(2n+1)24n2+4n+12n2+2n2(n2+n)=2n+1=2m+1=3(2m+1)2=12m2+12m+3=6m2+6m+1=2(3m2+3m)+1

Since (n^2+n) is an integer, the left hand side is even. Since (3m^2+3m) is an integer, the right hand side is odd and we have found a contradiction, therefore our hypothesis is false.

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.for question after 10 you should learn the basic property of logarithm...

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Please mark me as brainliest...