Question

a rhombus has a perimeter of 68 cm and a diagonal of 30 cm find the area of the Rhombus​

Answer 1

Answer:

240cm²

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Answer 2

Answer:

Area= 240 cm^2

Step-by-step explanation:

Using the formulas,

$a = \frac{pq}{2} \\ p = 4a \\ a = \sqrt{ {p}^{2} + {q \frac{}{} }^{2} \ } \div 2$

Solving for A,

$a = \frac{1}{4} p \sqrt{ {p}^{2} - 4 {p}^{2} }$

$\frac{1}{4}.30. \sqrt{6 {8}^{2} - 4.3 {0}^{2} } = 240c {m}^{2}$

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