Question

a rhombus has a perimeter of 68 M and one of its diagonal is 30 find the area of Rhombus

Answer 1

given
perimeter=68
4a=68
a=17
given one diagonal p=30
WKT
other diagonal q=(4a^2-p^2)^1/2
q=(4×17×17-30×30)^1/2
q=16
WKT area=pq/2
=30×16/2
=240

Answer 2

Answer:

Answer is 240m

Step-by-step explanation:

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