A rhombus has diagonals of length 8cm and 6cm.What is the perimeter
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The area of a rhombus = d1*d2/2 = 8*6/2 = 24 sq cm.
Half the diagonals are 8/2 = 4 cm and 6/2 = 3 cm.
So each side of the rhombus is [4^6+3^2]^0.5 = 5 cm.
The perimeter of the rhombus is thus 20 cm.
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Half the diagonals are 8/2 = 4 cm and 6/2 = 3 cm.
So each side of the rhombus is [4^6+3^2]^0.5 = 5 cm.
The perimeter of the rhombus is thus 20 cm.
please mark me as BRAINLIST
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