If each side of the rhombus is 40m and it's longer diagonal is 48m then the area of rhombu.
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Answered by
28
So we take longer diagonal as 48 m
If we draw the other diagonal too
Then we get 4 triangles actually right angled triangles
So the diagonals length gets halved
So we get base as 24 m for a particular triangle out of 4
Then hypotenuse becomes rhombus side qhich is equal to 40m
And then through pythagoras theorem the third side that is perpendicular comes as 32 = 64
If we double the length it will be the smaller diagonal
So we get both the diagonals
Now we know that area of rhombus is 1/2 ×product of duagonal
So area becomes (64×48)/2 = 1536m^2
Thank u★★★
#ckc
If we draw the other diagonal too
Then we get 4 triangles actually right angled triangles
So the diagonals length gets halved
So we get base as 24 m for a particular triangle out of 4
Then hypotenuse becomes rhombus side qhich is equal to 40m
And then through pythagoras theorem the third side that is perpendicular comes as 32 = 64
If we double the length it will be the smaller diagonal
So we get both the diagonals
Now we know that area of rhombus is 1/2 ×product of duagonal
So area becomes (64×48)/2 = 1536m^2
Thank u★★★
#ckc
Answered by
10
Answer:
longer diagonal as 48 m ( taken )
if we draw the other diagonal too
then we get 4 triangles actually right angled triangles
so the diagonals length gets halved
so we get base as 24 m for a particular triangle out of 4
then hypotenuse becomes rhombus side is equal to 40m
and then through pythagoras theorem the side that is perpendicular comes as 32 = 64
if we double the length it will be the smaller diagonal
so we get both the diagonals
now we know that area of rhombus is 1/2 ×product of diagonal
so area becomes (64×48)/2 = 1536m^2
hope it helps you..
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