Question

If each side of the rhombus is 40m and it's longer diagonal is 48m then the area of rhombu.

Answer 1

So we take longer diagonal as 48 m

If we draw the other diagonal too

Then we get 4 triangles actually right angled triangles

So the diagonals length gets halved

So we get base as 24 m for a particular triangle out of 4

Then hypotenuse becomes rhombus side qhich is equal to 40m

And then through pythagoras theorem the third side that is perpendicular comes as 32 = 64

If we double the length it will be the smaller diagonal

So we get both the diagonals

Now we know that area of rhombus is 1/2 ×product of duagonal

So area becomes (64×48)/2 = 1536m^2

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Answer 2

Answer:

longer diagonal as 48 m ( taken )

if we draw the other diagonal too

then we get 4 triangles actually right angled triangles

so the diagonals length gets halved

so we get base as 24 m for a particular triangle out of 4

then hypotenuse becomes rhombus side is equal to 40m

and then through pythagoras theorem the side that is perpendicular comes as 32 = 64

if we double the length it will be the smaller diagonal

so we get both the diagonals

now we know that area of rhombus is 1/2 ×product of diagonal

so area becomes (64×48)/2 = 1536m^2

hope it helps you..