Question

a rhombus has perimeter 64 and one of the diagonals is 22 metre prove that the area of the Rhombus is 66 root 15 square​

Answer 1

Answer:

d2=6√15

Step-by-step explanation:

primater of rhombus is= 64

4a=64

a=64/4

a=16

at the same time diagonals(d1)=22

area of rhombus is =1/2×d1×d2

66√15=1/2×22×d2

66√15=11×d2

6√15=d2

then other diagonal is d2= 6√15

so, then prove that area of rhombus is 66√15

d1=22,d2=6√15

then area of rhombus =1/2×d1×d2

=1/2×22×6√15

=66√15

tq so much ............

Answer 2

Answer:

side of the Rhombus=64/4=16m

one diagonal=22m

other diagonal=2V16^2-11^2

= 2 v256-121 = 2v 135 = 2x3V15

= 6V15

Area = d1xd2/2=22x6 v15/2=66V15

Area of RHOMBUS = 66 v15