A rhombus shaped field has green grass for 18 cows to grace. if each side of rhombus is 30 m and its longer diagonal is 48m, how much area of the grass field with each cow be getting
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hence each cow gets 80 meteres in rhombus field to graze
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Let abcd is a rhombus.
And ac is big daigonal and bd is small
And there intersectiion be 0 and it is perpendicular
So in triangle aob
O is 90
A0 =1/2*48
A0 = 24
By pythagoras theorem
900-576=324
And its square root is 18
So now are of rhombus =1/2*36*48
=18*48
=864
So each cow= 864/18
=48
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