Question

A rhombus shaped field has green grass for 18 cows to graze.If each side of the rhombus is 30m and its longer diagonal is 48m,how muck area of grass field will each cow be getting?​

Answer 1

Answer:

48m²

Step-by-step explanation:

Grass each cow gets=area of field/number of cows

area of field=1/1 d1*d2=1/2*48*x

to find 1/2 of x we use pythogaras theorem

x²+24²=30²

x²+576=900

x=√900-576

x=18

so,area of field=1/2*48*36=864m²

grass each cow gets=864/18=48m²

Answer 2

$\huge\tt{\underline{\underline{Solution:-}}}$

a = 30m

b = 30m

c = 48m.

Semi-perimeter , s = $\huge\sf\frac{30+30+48}{2}$ = 54m.

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$\underline\textsf{By\:using\:heron's\:formula:-}$

$\sf\sqrt{s(s-a)(s-b)(s-c)}$

$\sf\sqrt{54(54-30)(54-30)(54-48)}$

$\sf\sqrt{54(24)(24)(6)}$

=> 3 * 6*24 = 432${m}^{2}$

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Area of field = 2 * Area of ∆BCD

(2*432)${m}^{2}$ = 864${m}^{2}$

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Area for grazing for 1 cow = $\huge\sf\frac{864}{18}$ = 48${m}^{2}$

Therefore, Each cow will get 48${m}^{2}$ area for grass field.