Question

A block of 10 g slides on smooth horizontal surface with 20 m/s towards a spring
100 N/m placed horizontally (as shown in figure). The maximum compression
ce with 20 m/s towards a spring of spring constant
v= 20 m/s
10g) - 7000mm
(1) 2m
(2) 0.2m
(3) 20m
(4) 0.75m​

Answer 1

Answer:

0.2m

Explanation:

Use the laws of conservation of energy.

Answer 2

Given that,

Mass of the block, m = 10 g = 0.01 kg

It is moving with a speed of 20 m/s towards a spring.

Spring constant of the spring, k = 100 N/m

To find :

The maximum compression  in the spring constant.

Solution :

When the bock moves, the kinetic energy is converted to elastic potential energy as :

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2$

x is the compression in the spring

$x=\sqrt{\dfrac{mv^2}{k}} \\\\x=\sqrt{\dfrac{0.01\times (20)^2}{100}} \\\\x=0.2\ m$

So, the compression in the spring is 0.2 meters.

Learn more,

Conservation of energy

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