a rhombus shaped field has green grass for 18 cows to graze. if each side of the rhombus is 30m and it's longer diagonal is 48m, how much area of grass field will each cow be getting?
Answers
Answer:
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Answer:
Let ABCD is a rhombus and length of each side is 30
Length of diagonal AC is 48
From Δ ABC,
Let AB =a =30
AC = b =48
BC = c = 30
Now s = (a+b+c)/2
=> s = (30+48+30)/2
=> s = 108/2
=> s = 54 m
Now area of Δ ABC = √{s*(s-a)*(s-b)*(s-c)}
= √{54*(54-30)*(54-48)*(54-30)}
= √{54*24*6*24}
= √{9*6*24*6*24}
= 3*6*24
= 432 m2
Area of rhombus ABCD = 2* area of Δ ABC (since area of Δ ABC = area of Δ ACD)
= 2* 432
= 864 m2
Now area of grash for 18 cows = 864 m2
So area of grash for 1 cows = 864/18 m2 = 48 m2