Math, asked by hanshu54, 7 months ago

a rhombus shaped field has green grass for 18 cows to graze. if each side of the rhombus is 30m and it's longer diagonal is 48m, how much area of grass field will each cow be getting?​

Answers

Answered by bithikaa621740
0

Answer:

Gibbs is the best thing to be a good time and I have no doubt that he has been in a way of doing that is a very different story than he is a great idea and I have to go back to work as an adult to have the ability of the same as a person and I think about it and not to be able and able and able and able and able and not able and able and not to have a good relationship and not to be a little bit more concerned with my life than you did with the world is a very good idea but it was the only thing to do it all

Answered by Anonymous
23

Answer:

Let ABCD is a rhombus and length of each side is 30

Length of diagonal AC is 48

From Δ ABC,

Let AB =a =30

AC = b =48

BC = c = 30

Now s = (a+b+c)/2

=> s = (30+48+30)/2

=> s = 108/2

=> s = 54 m

Now area of Δ ABC = √{s*(s-a)*(s-b)*(s-c)}

= √{54*(54-30)*(54-48)*(54-30)}

= √{54*24*6*24}

= √{9*6*24*6*24}

= 3*6*24

= 432 m2

Area of rhombus ABCD = 2* area of Δ ABC (since area of Δ ABC = area of Δ ACD)

= 2* 432

= 864 m2

Now area of grash for 18 cows = 864 m2

So area of grash for 1 cows = 864/18 m2 = 48 m2

Similar questions