A rifle of mass 2 kg fires a bullet of mass 20 g with velocity of 150 m/s. Because of this, the gun is pushed back with a velocity of
(a) 1500 m/s
(b) 1.5 m/s
(c) 15 m/s
(d) -1.5 m/s
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Answer:
The gun is pushed back with a velocity of 0.66 m/s.
Explanation:
Given:
- Mass of rifle = 2kg
- Mass of bullet = 20g
- Velocity = 150 m/s
To Find:
- Velocity by which gun is pushed back = ?
Solution:
Velocity by which gun is pushed back = ?
Momentum = mass × velocity
Momentum before gun is fired = momentum of gun after fired + momentum of gun before fired.
Consider velocity of gun as ‘v’ m/s.
Bullet of mass = 20g = 0.02kg
By conservation of momentum,
=> m1v1 + m2v2
=> (2kg + 0.02kg) × 0 = (2kg × v m/s) + (0.02kg × 150 m/s)
=> 0 = 2v + 3
=> v = 2/3
=> v = 0.66 m/s
∴ Gun is pushed back with a velocity of 0.66 m/s.
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