good evening
solve question 9
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(i) 0
(ii) 0
Step-by-step explanation:
Verify: (i) x^3+y^3=(x+y)(x^2-xy+y^2)
=x^3+y^3=x^3+y^3[(x+y)(x^2-xy+y^2)=x^3+y^3]
=x^3-x^3+y^3=y^3[x^3 is transposed to the other side]
=y^3=y^3
=y^3-y^3=0[y^3 is transposed to the other side]
=0=0
=0
Answer: 0
(ii) x^3-y^3=(x-y)(x^2+xy+y^2)
=x^3-y^3=x^3-y^3[(x-y)(x^2+xy+y^2)=x^3-y^3]
=x^3-y^3+y^3=x^3[-y^3 is transposed to the other side]
=y^3-y^3=x^3-x^3[x^3 is transposed to the other side]
=0=0
=0
Answer: 0
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