a rifle with a mass of 0.02kg fires a 0.05g bullet with an initial velocity of 100m/s.what is the recoil velocity of the rifle?
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here use concept of linear momentum conservation
this is also Newton's third law
it's formula is m₁v₁ = m₂v₂ so
apply this formula
0.02 x v = 0.05x10⁻² x100
v = 5/2
this is also Newton's third law
it's formula is m₁v₁ = m₂v₂ so
apply this formula
0.02 x v = 0.05x10⁻² x100
v = 5/2
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