A right angle triangle whose sides are 15 cm and 20 cm other than hypotenuse is made to revolve about its hypotenuse find the volume and surface area of the double cone so formed choose the value of pi as found appropriate
Answers
Answer:
Volume of cone V = 4710 cm^3
Total surface area , T.S.A = 1884cm^2
Step-by-step explanation:
It is given that,
A right angle triangle whose sides are 15 cm and 20 cm other than hypotenuse is made to revolve about its hypotenuse
A cone is formed.
The base radius, r = 15cm
The height, h = 20cm
To find hypotenuse
Hypotenuse^2 = 15^2 +20^2 =225 + 400 = 625
Hypotenuse = 25
Lateral length of cone, l = 25
To find total surface area of cone
Total Surface Area A = Lateral surface area + base area
Lateral surface area L.S. A = πrl = 3.14 x 15 x 25 =1177.5 cm^2
Base area = πr^2 = 3.14 x 15 x 15 = 706.5 cm^2
Total surface area , T.S.A = Lateral surface area + base area =1177.5 + 706.5 =1884cm^2
To find volume of cone
Volume of cone,V = 1/3πr^2h
V = 1/3 x 3.14 x 15 x 15 x 20
V = 4710 cm^3
Answer:
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