A right-angled triangle ABC is such that:
AB = 3.5 cm, BC = 2.3 cm and ∠B = 90°
Find ∠C correct to one decimal place.
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Answer:
AC^2 = AB^2 + BC^2
=(3.5)^2 + (2.3)^2
=12.25 + 5.29
=17.54
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