Math, asked by 2464484, 4 months ago

A right-angled triangle ABC is such that:

AB = 3.5 cm, BC = 2.3 cm and ∠B = 90°

Find ∠C correct to one decimal place.

Answers

Answered by ahla22
1

Answer:

AC^2 = AB^2 + BC^2

=(3.5)^2 + (2.3)^2

=12.25 + 5.29

=17.54

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