Question

a right angled triangle has base 8cm and height of 6cm find lenghts of periphery and area

Answer 1

Hii friend,

Let ∆ABC be right angled triangle right angle At B.

In which,

AC be the Hypotenuse , BC be the base and AB be the Perpendicular.

BC = 8 CM , AC = 6 CM And AB = ?

By pythagoras theroem ,

AC² = (AB)² + (BC)²

AB² = (BC)² - (AC)²

AB² = (8)² - (6)²

AB² = 64 - 36

AB²= 28

AB = ✓28 = 5.29 CM.

Area of triangle = 1/2 × BC × AB

=> 1/2 × 8 × 5.29 = 42.32/2 = 21.16 CM².

HOPE IT WILL HELP YOU..... :-)

Answer 2

Hi.

Here is your answer---

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Given---

  Base(B) = 8 cm.
Height(P) = 6 cm.

Using the Pythagoras theorem,
                                      H² = P² + B²
                                     (H)² = 6² + 8²
                                      H² = 36 + 64
                                      H² = 100
                                      H = √100
                                      H = 10 cm

Thus, the length of the Periphery is 10 cm.

For Area,
 
   Using the Formula,
       Area of the Triangle = 1/2 × Base × Height
                                       = 1/2 × 8 × 6
                                       = 12 cm².

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Hope it helps.

Have a nice day.