Plz... ans my question immediately... n plz explain Ur ans in such a way that I can easily understand.
Attachments:
Answers
Answered by
2
The first method is the right one.
1st shell=2elec.
2nd shell=8 elec.
3rd shell=18 elec.
4th shell=32 elec.
However, if the atomic no. is not enough to place 18 electrons in the third shell, for example if you have the atomic no.=27.
Then, you must place electrons as such:
1st shell=2 electrons
2nd shell=8 electrons
Now you have only 17 electrons, so you cant use the formula 2n^2 to place the electrons or it would place 18 electrons in the 3rd shell, but you have only 17 electrons, so you must again place only 8 electrons, even in the third shell.
Then again 8 electrons in the 4th shell and then you are left witj only one electron, which is to be placed in the outermost/valence shell.
Thus, the electronic configuration for atomic no. 27 will be: 2,8,8,8,1.
Same rules apply to other atomic nos. also.
Hope you understood the concept.
1st shell=2elec.
2nd shell=8 elec.
3rd shell=18 elec.
4th shell=32 elec.
However, if the atomic no. is not enough to place 18 electrons in the third shell, for example if you have the atomic no.=27.
Then, you must place electrons as such:
1st shell=2 electrons
2nd shell=8 electrons
Now you have only 17 electrons, so you cant use the formula 2n^2 to place the electrons or it would place 18 electrons in the 3rd shell, but you have only 17 electrons, so you must again place only 8 electrons, even in the third shell.
Then again 8 electrons in the 4th shell and then you are left witj only one electron, which is to be placed in the outermost/valence shell.
Thus, the electronic configuration for atomic no. 27 will be: 2,8,8,8,1.
Same rules apply to other atomic nos. also.
Hope you understood the concept.
Anonymous:
good answer!
thanx
Answered by
2
Hey there!!!
don't get in tension. Actually both the methods are correct but Now a days everone use 2nd method because it's the latest one. Actually now it is found that Max no of electrons any shell can hold is 8. So Both the methods are correct But use 2nd one.
Hope it helped......
don't get in tension. Actually both the methods are correct but Now a days everone use 2nd method because it's the latest one. Actually now it is found that Max no of electrons any shell can hold is 8. So Both the methods are correct But use 2nd one.
Hope it helped......
Similar questions