Question

A right angled triangle has the largest side as 13cm and one of the sides containing the right angle as 12 cm . it's area in cm square is ?

Answer 1

Given :-
hypotenus = 13 cm
other side = 12 cm
area of triangle = ?
By pythagorus theorem ,
h^2 = b^2 + p ^2
(13)^2 = (12)^2 + p^2
169 = 144 + p^2
p^2 = 169 - 144
p = 5 cm
now ,
area of triangle = 1/2 × base × height
= 1/2 × 12 × 5
= 6 × 5
= 30 cm^2

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Answer 2

GIVEN –

the largest side (hypotenuse) = 13 cm
one side = 12 cm

first we have to find other side .

${13}^{2} = {12}^{2} + {x}^{2}$
${x}^{2} = {13}^{2} - {12}^{2} \\ {x}^{2} = 169 - 144 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = \sqrt{5 \times 5 } \\ x = 5$
Now,

let one side be height of the right angled triangle
and other side be base of the right angled triangle

WE KNOW THAT-

Area of right angled triangle = 1/2 × base × height

1/2 × 5 × 12
= 5 × 6
= 30

So, the Area of right angled triangle is 30 sq.cm

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