a right angled triangle having perimeter 120cm has its two perpendicular sides in the ratio 5 : 12. Find the lengths of its sides
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Answered by
210
let, two perpendicular sides are 5x and 12x
then,
hypotenuse = √{(5x)^2 + (12x)^2}
=√(25x^2 + 144x^2)
=√(169x^2)
=13x
now,
13x + 12x + 5x = 120
=> 30x = 120
=> x = 120/30 = 4
hence, lengths of its sides are:-
5x =5×4 =20 cm
12x =12×4 =48 cm
13x =13×4 =52 cm
_________________
I hope this will help you..
then,
hypotenuse = √{(5x)^2 + (12x)^2}
=√(25x^2 + 144x^2)
=√(169x^2)
=13x
now,
13x + 12x + 5x = 120
=> 30x = 120
=> x = 120/30 = 4
hence, lengths of its sides are:-
5x =5×4 =20 cm
12x =12×4 =48 cm
13x =13×4 =52 cm
_________________
I hope this will help you..
saikriushnan:
thank you for this answer your genius
Answered by
23
Answer:
the lengths are 20,48 and 52 cm
Explanation:
hope this helps!!
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