Question

A right - angled triangle is isosceles. if the of the hypotenuse is 50m, what is the length of equal sides ?​

Answer 1

let x = height of ∆ = base of ∆ .

then , by Pythagoras Theorem

(x)² + (x)² = 50

2(x)² = 50

$\sf {(x)}^{2} = \frac{50}{2} = 25 \: \: \implies \: \: x = \sqrt{25 } = 5cm$

∴ Height of isosceles ∆ = 5cm

∴ Base of isosceles ∆ = 5cm

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Answer 2

Explanation:

let x = height of ∆ = base of ∆ .

then , by Pythagoras Theorem

(x)² + (x)² = 50

2(x)² = 50

$\sf {(x)}^{2} = \frac{50}{2} = 25 \: \: \implies \: \: x = \sqrt{25 } = 5cm$

∴ Height of isosceles ∆ = 5cm

∴ Base of isosceles ∆ = 5cm

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